Audit: print template debug info in Jenkins logs

This commit is contained in:
2026-04-26 14:03:17 +02:00
parent 848b8aae54
commit f7b48450df

View File

@@ -60,6 +60,9 @@ cp "$TMP_DEBUG" "$DEBUG_FILE"
if [ "$debug_rc" -ne 0 ]; then
echo "WARNING: template debug command failed (rc=${debug_rc})" >> "$DEBUG_FILE"
fi
echo "---- TEMPLATE DEBUG (staging) ----"
cat "$DEBUG_FILE"
echo "---- END TEMPLATE DEBUG ----"
set +e
STAGING_AUDIT_PROJECT_NAME="$STAGING_AUDIT_PROJECT_NAME" REMOTE_CMD="$REMOTE_CMD" AUDIT_TIMEOUT_SECONDS="$AUDIT_TIMEOUT_SECONDS" python3 - <<'PY' > "$TMP_FILE"